JEE Main Rank Predictor 2027
Enter your correct and wrong answers (or your raw marks out of 300) to estimate your NTA Percentile and All India Rank (AIR) for JEE Main 2027, based on past session shifts and cutoffs.
Estimate only based on standard normalization formulas. Actual NTA percentile depends on your shift difficulty and raw candidate score distribution.
How to use it
- Choose whether you know your individual answers or your total marks out of 300.
- Enter correct (+4) and wrong (-1) answers out of 75 compulsory questions.
- Select your category (General, EWS, OBC-NCL, SC, ST) to see JEE Advanced qualifying status.
- Check your estimated percentile and expected All India Rank (AIR).
Common questions
How is the JEE Main score calculated?
JEE Main paper has 75 questions (25 Math, 25 Physics, 25 Chemistry). Each correct answer gives +4, each incorrect answer gives -1, and unattempted gives 0. Maximum total marks are 300.
What is the difference between marks and percentile in JEE Main?
NTA normalizes scores across multiple shifts into percentiles from 100 to 0. A percentile of 99 means you scored better than 99% of all candidates who appeared in that session.
What percentile is required to qualify for JEE Advanced?
Typically ~93.2 percentile for General, ~81.3 for Gen-EWS, ~79.2 for OBC-NCL, ~60 for SC, and ~46.6 for ST.
What rank is needed for a top NIT or IIIT?
For top NITs (Trichy, Surathkal, Warangal) in Computer Science, an AIR under 4,000 (approx. 99.7+ percentile) is generally required for Open Category under Other State quota.
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